Print decimal value of a char

Question

Program to print decimal value of a char:

#include

int main(void){

  char ch = \'AB\';
  printf(\"ch is %d\\n\",ch);

}

Why i

Answer 1

C11 $6.4.4.4 (Character constants):

A multi-char always resolves to an int, but that the exact value is “implementation-dependent”. That is, different compilers may resolve the same multi-char to different integers. This is a portability problem, and it is one of the reasons multi-chars are discouraged.

It means int ch = 'AB'; is ok for int type.But, If it were declared as type char, the second byte would not be retained.

So use

char ch = 'A';

instead of

char ch = 'AB';

and use %c format specifier for char type.

printf("ch is %c\n",ch);