Defining namespaced member vs free functions without qualification

Question

I sometimes declare classes in nested namespaces and when it comes to defining their member functions, I prefer not to have to qualify each one with these nested namespace name

Answer 1

Perhaps I'm getting this wrong but if you have:

// example.h
namespace SomeNamespace
{
    class SomeClass
    {
    public:
        void someMemberFunction();
    };

    void someFreeFunction();
};

You can also simply write:

#include "example.h"

// example.cpp
namespace SomeNamespace
{
    void SomeClass::someMemberFunction()
    {
    }

    void someFreeFunction()
    {
    }
}