Is it possible to do a bash brace expansion using a variable bound without using eval?

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臣服心动
臣服心动 2021-01-27 02:59

Consider the following script.

#!/bin/bash

echo {00..99}
n=99
echo {00..$n}

The output of this script is:

00 01 02 03 04 05 06         


        
3条回答
  •  长发绾君心
    2021-01-27 03:15

    Not sure if this meets your requirements, as it doesn't use braces, but (with GNU seq at least) the following produces the desired output:

    $ n=99
    $ seq -f%02.0f -s' ' 00 "$n"
    00 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99
    

    The "-f" option produces the zero-padding, and the "-d" uses spaces to separate, rather than newlines.

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