How to check if all the digits of a number are odd in python?

Question

I was told to solve a problem in which I would have to find out the number of 4-digit numbers which are all composed of odd digits. I tried the following python code:

Answer 1

I believe something like this would work if you're looking to model what you already have, but I echo the comment by yotommy that some intuitive multiplication would do the trick.

 for a in range(1111,10000):
       allOdd = True
       for b in str(a):
           if int(b) % 2 == 0:
               allOdd = False
       if(allOdd):
          new_list.append(a)