C++ new / new[], how is it allocating memory?

Question

I would like to now how those instructions are allocating memory.

For example what if I got code:

x = new int[5]; 
y = new int[5];

If t

Answer 1

You didn't find it in the manual because it's not specified by the standard. That is, most of the time x and y will be side by side (go ahead and cout<< hex << their addresses).

But nothing in the standard forces this so you can't rely on it.