Why use SomeType[1] instead of SomeType* as last member in structs

Question

I saw in the code next statement:

SomeType someVar[1];

Later someVar is used as a pointer to SomeType. Why would one

Answer 1

SomeType someVar[1];

someVar is an array of type SomeType with 1 element.

SomeType* someVar;

someVar is a pointer (dangling still, you didn't point it to anything yet) of type SomeType.

And you can use the name of an array on its own as a shorthand for a pointer to the first element of that array.

Will Dean