Sequential numbers in a list haskell

Question

I am new to haskell and I was attempting a few coding problems that I previously completed for java, however the following problem has me stumped.

Basically the idea is

Answer 1

One way would be to use pattern matching to look for consecutive ones at the head of the list, and advance down the list until you find them, or you run out of elements to look at.

consecutiveOnes [] = False
consecutiveOnes (1:1:_) = True
consecutiveOnes (_:xs) = consecutiveOnes xs