Why comparing matrices is not evaluated as boolean in Octave?

Question

Im new to Octave and playing around with the console.

why when comparing matrices, the expression is not evaluates as boolean :

example:

>>         


        

Answer 1

Sardar's answer is correct, but when it comes to computational time, I think that my alternative answer is better: You can as well check that all elements of the boolean matrix A == A are 1, i.e., that the sum of 1s in the matrix A==A equals the number of elements of A, i.e:

sum((A == A)(:)) == numel(A)

ans = 1

Where the operator (:) simply vectorizes the matrix A==A so that it can be added with sum(). Compare the two answers when you matrix is quite big, for instance by defining A = rand(1e4), the computation time is considerably different...