Windsor MixIn is a Singleton?

Question

I have a MixIn that requires some state to operate.

I am registering it as so..

    container.Register(Component.For(Of ICat) _
                        .         


        

Answer 1

If you register the mixin with transcient lifestyle, it will create a new instance for each component:

container.Register(
    Component.For().ImplementedBy()
        .LifestyleTransient()
        .Proxy.MixIns(m => m.Component("mixin")),
    Component.For().LifestyleTransient().Named("mixin")
);