Several unary operators in C and C++

Question

Is it standard-conforming to use expressions like

int i = 1;
+-+-+i;

and how the sign of i variable is determined?

Answer 1

i isn't modified (C: without intervening sequence points|C++: in an unsequenced manner) so it's legal. You're just creating a new temporary with each operator.

The unary + doesn't even do anything, so all you have is two negations which just give 1 for that expression. The variable i itself is never changed.