Several unary operators in C and C++

Question

Is it standard-conforming to use expressions like

int i = 1;
+-+-+i;

and how the sign of i variable is determined?

Answer 1

Your operators has no side effect, +i do nothing with int itself and you do not use the temporary generated value but remove + that do nothing and you have -(-i) witch is equal to i itself.(removing + in the code will convert the operator, I mean remove it in computation because it has no effect)