Unexpected NumberFormatException while parsing a hex string to an int value

Question

I want to parse an String containing 8 hex-digits (4bytes) but i got an NumberFormatException. What is wrong here?

assertThat(Integer.parseInt(\"FFFF4C6A\",16),i         


        

Answer 1

I don't know the assertThat() method, but your hexadecimal number "FFFF4C6A" is to big for an integer.

For example, if you write :

int number = Integer.parseInt("FFFF4C6A",16)

you'll get the same error. A correct way to write the code would be :

double number = Integer.parseInt("FFFF4C6A",16)