Printing all elements of an array in one println statement in Java [duplicate]

Answer 1

expected to take a compile or run-time error.I took an output.It's "[I@1ba4806".What's the reason of it in Java?

Because currently the toString method from Object class is getting invoked, it looks like this

public String toString() {
    return getClass().getName() + "@" + Integer.toHexString(hashCode());
}

Thats why you see [I@1ba4806

You can print array content using Arrays.toString which is overloaded method in Arrays class to print the array.

System.out.println(Arrays.toString(a));

For int[] parameters the method implementation looks like

public static String toString(int[] a) {
    if (a == null)
        return "null";
    int iMax = a.length - 1;
    if (iMax == -1)
        return "[]";

    StringBuilder b = new StringBuilder();
    b.append('[');
    for (int i = 0; ; i++) {
        b.append(a[i]);
        if (i == iMax)
            return b.append(']').toString();
        b.append(", ");
    }
}