bash — boolean expression evaluation without condition

Question

I tried to play around with bash, and even tried documentation and few threads though I cannot seem to get it right.

S=(true false)
if (( ${S[0]} || ${S[1]} ))
t         


        

Answer 1

Instead of S=(true false), you need to create your array like this:

S=(1 0)

Then this if block:

if (( ${S[0]} || ${S[1]} ))
then
    echo "true"
else
    echo "false"
fi

will output:

true

Please note that true/false are treated as literal strings "true" and "false" in BASH.