Digital Root without loops Python

Question

def digit_sum(n):
    \'\'\'(int)->number
    Returns the sum of all the digits in the given integer, n\'\'\'
    if n<10:
        return n
    return n%10 + digit         


        

Answer 1

Try this:

def num(n) :   
     sum = 0   #provided sum as 0
     for i in str(n): 
         a = int(n) % 10    #taken variable a 
         sum  = sum + a   #put the sum.
         n = n/10
     print(sum)    
     if sum < 10:    
         print(str(sum) + "=this is a digital root")
     else:
         num(sum)