How to create instance of the unkown type?

Question

I have a couple of functions which requires exact argument type (aka T):

private  void doWork1(T _obj) {...}
private  void doWork2         


        

Answer 1

You can use Number or Object, which are both common supertypes of Integer and Double.

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However, the generics are unnecessary:

private  void doWork1(T _obj) {...}

is identical to

private void doWork1(Object _obj) {...}

after erasure.

The only point of having a type variable for an input parameter is if:

• You need to indicate that the generics of another input parameter need to be related, e.g. you are passing T _obj and List _list.

  Note that you don't need a generic type for T _obj1 and T _obj2, though - that degenerates to the upper bound of T (e.g. Object);

• If you need it to be related to the return type:

   T doWork1(T _obj) { ... }
  

You don't need either case here, so just remove the unnecessary complication.