Your C++ guru is wrong (provided you understood them, gurus tend to talk in cryptic messages). Const-qualifier on the argument type itself is not a part of a function signature at all.
For example, void foo(int* const ); is no different from void foo(int* ). Please note, it is not the same as const qualification of the indirect object, like void foo(const int* ) is different from void foo(int* ).
In your particular case, void test(int x) is the same as void test(int const x)
