Returning an odd or even number from array

Question

Just need help in identifying what I am doing wrong on this codewar challenge.

I realize this may be easy for some but please note I am just a beginner with Javascript.

Answer 1

I've found 2 issues inside your code block. You have to run loop over array length instead of entire array otherwise you can use foreach loop. You need to return odd/even value after finishing your loop. Please check updated code as follows, hope it'll help.

function findOutlier(integers){

    var even = [];
    var odd = [];

    for (var i = 0; i < integers.length; i++) {
        if (integers[i] % 2 === 0) {
            even.push(integers[i]);
        } else {
            odd.push(integers[i]);
        }
    }
    if (even.length === 1) {
        console.log("OK..1");
        return even;
    } else {
        console.log("OK..2");
        return odd;
    }
}