Reference initialization in C++

Question

Greetings, everyone!

Examining my own code, I came up to this interesting line:

const CString &refStr = ( CheckCondition() ) ? _T(\"foo\") : _T(\"bar         


        

Answer 1

You are missing something - it is completely legal code, and in fact such code is one of the commonest and best uses of the conditional operator. It's always a mistake to think that the compiler must internally do things in the same order that the code is layed out on the page - it is perfectly at liberty to evaluate the conditional operator (which is justv another expression) and then use the result to perform the initialisation.

As for a goto, there is no way of using one in an initialisation. And if an exception is thrown, the reference is deemed never to have been created in the first place.