Reading RIP register gives next instruction's address?

Question

I try to read the value of x86_64 register rip. Here is what objdump shows.

4017ec: 48 8d 35 00 00 00 00  lea    0x0(%rip),%rsi
4017f3:         


        

Answer 1

rip always hold the address of the next instruction while running the current instruction. If fact updating rip by the address of the next instruction, is part of the execution process of the current instruction.