Multiple command output into variable Bash script with $()

Question

I reviewed the multiple threads on this and am still having issues, here is the command I\'m trying to execute. Commands without the $() print the desired output t

Answer 1

That is correct:

MODEL3=$(/usr/sbin/getSystemId | grep "Product Name" | awk '{print $4}')

But you can write the same without grep:

MODEL3=$(/usr/sbin/getSystemId | awk '/Product Name/{print $4}')

Now you have the result in the MODEL3 variable and you can use it further as $MODEL3:

echo "$MODEL3"