Negating multiple conditions in Bash

Question

I realize this is a simple question, but I am finding a hard time getting an answer due to the finnicky syntax requirements in bash. I have the following script:

Answer 1

Remember (or learn!) that [ is not part of shell syntax, it is a command.

If you want to group together multiple commands, then you should use { }

if ! { [ -z "$1" ] || [ -z "$2" ]; }

Note that the parser expects to see a line ending or semicolon before the closing }.

For the record, I'd avoid the negation and use && here:

if [ -n "$1" ] && [ -n "$2" ]

...and since you specified bash, you may as well take advantage of the enhanced test construct:

if [[ -n $1 && -n $2 ]]