Not null-terminating a C-style string

Question

Given a string , say ,

char *str = \"Hello,StackOverflow!\"
char newStr[30];
int l = strlen(str);
for(int i =0 ; i

        

Answer 1

I would suspect that most of the time it would keep printing past the "!" and keep going in memory until it hits a NULL. Which could result in a crash, but doesn't have to.

This is why it's best to either:

memset(newStr, 0, 30);

or

// This works because string literals guarantee a '\0' is present
// but the strlen returns everything up until the '\0'
int l = strlen(str) + 1;

this works too, but I don't feel it's as clear as adding one to strlen:

for(i =0 ; i<=l ; i ++ )

As the defination of strlen implies you need to.