Python dictionary; sum values of the same keys

Question

It might be simple but im just a beginner. If i have this dictionary;

ds = {\"ABab\": 6.25, \"aBab\": 6.25, \"Abab\": 6.25, \"abab\": 6.25, \"ABab\": 6.25, \"aBa         


        

Answer 1

As noted already, you can't store this data in a dictionary. You could store it in some other form such as a list of tuples.

ds = [("ABab", 6.25), ("aBab", 6.25), ("Abab", 6.25), ("abab", 6.25),
      ("ABab", 6.25), ("aBab", 6.25), ("Abab", 6.25), ("abab", 6.25),
      ("ABab", 6.25), ("aBab", 6.25), ("Abab", 6.25), ("abab", 6.25),
      ("ABab", 6.25), ("aBab", 6.25), ("Abab", 6.25), ("abab", 6.25)]

Then you can make a dictionary of the totals by first finding the unique keys and then summing the values of the tuples which have that key as their first value.

keys = set(k for k, _ in ds)
totals = {unique_key: sum(v for k, v in ds if k==unique_key) 
    for unique_key in keys}

Or another way (probably better)

totals = {}
for key, value in ds:
    totals[key] = totals.get(key, 0) + value