How do I convert from a char array [char; N] to a string slice &str?

Question

Given a fixed-length char array such as:

let s: [char; 5] = [\'h\', \'e\', \'l\', \'l\', \'o\'];

How do I obtain a &str<

Answer 1

You can't without some allocation, which means you will end up with a String.

let s2: String = s.iter().collect();

The problem is that strings in Rust are not collections of chars, they are UTF-8, which is an encoding without a fixed size per character.

For example, the array in this case would take 5 x 32-bits for a total of 20 bytes. The data of the string would take 5 bytes total (although there's also 3 pointer-sized values, so the overall String takes more memory in this case).

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We start with the array and call []::iter, which yields values of type &char. We then use Iterator::collect to convert the Iterator into a String. This uses the iterator's size_hint to pre-allocate space in the String, reducing the need for extra allocations.