Is there an efficient way to solve the following problem:
lst = [1,2,3,4,5]
indexes_to_remove = [0,2,4]
#result
lst = [2,4]
My solution
<
In order to remove certain items from lst based on a list of indices indexes_to_remove, what you can do is sort the elements in indexes_to_remove in reverse order, and then remove them from lst in a for loop, ensuring in this way that each new index to remove is lower than the previous and hence the change in size of the list won't affect the new items to remove:
for i in sorted(indexes_to_remove, reverse=True):
del lst[i]
Output
[2, 4]