Arranging by Alphabetical Order

Question

I\'m new to Java and I\'m trying to arrange an arrayList of terms in alphabetical order. (A term is defined as a char and an int) (e.g. {Term(\'Z\',4),Term(\'C\',3),Term(\

Answer 1

You can use the Collection class and sort the list of term you have, you need only to make the class Term comparable

Example:

public class Term implements Comparable {
    .....
    //  .....
    //  criteria to sort is the char
    @Override
    public int compareTo(Term o) {
        if (o.getLetter()> this.letter) {
            return 1;
        } else if (o.getLetter() < this.letter) {
            return -1;

        } else {
            return 0;
        }

    }

---

public static void main(String[] args) {
    // test
    List myTermList = new ArrayList<>();
    myTermList.add(new Term('Z', 4));
    myTermList.add(new Term('Q', 2));
    myTermList.add(new Term('c', 3));
    // check how the look like
    System.out.println("This is the list unsorted: " + myTermList);
    // now sort them
    Collections.sort(myTermList);
    // check how the look like
    System.out.println("This is the list SORTED: " + myTermList);
}

Edit>

if you dont want to implement comparable then modify this:

res = maxtest.compareTo(maxtest2);

because this is not valid since maxtest and maxtest2 are primitives and not objects...

use instead

res = Character.compare(maxtest, maxtest2);

and then use the result to verify your logic and make decisions:

if (res >1) {
            System.out.println("bigger");

        }else if (res<1) {
            System.out.println("smaller");

        }else {
            System.out.println("same");

        }