Computing sum of values in array

Question

The problem im getting is that with oddSum the value outputted is the same as evenSum, and the value for sum of all elements is 0.

I cant quite see where im going wrong

Answer 1

You are getting same value for even and odd because you are printing the same value: -

System.out.print("Sum of odd elements: " + evenSum);

Also, your final sum is zero because you are making out all the elements of your original array as zero, as you are swapping your elements with the elements in evenData and oddData, which are zero initially.

int temp = data[index];
data[index] = evenData[index]; // This code assigns a value 0 to current index.
evenData[index] = temp;

So, you are iterating your array, and assigning 0 to each of your index, while adding the previous element to the new array.

---

I would say that you are needlessly using 2 extra array and 3 extra loops. Why not just create a sum in the place where you are iterating your original array?

In fact, all your sums can be computed in a single loop: -

for(int index = 0; index < data.length; index++)
{
    sum += data[index];

    if (data[index] % 2 == 0)
    {
        // int temp = data[index];
        // data[index] = evenData[index];
        // evenData[index] = temp;

        evenSum += data[index];
    }
    else
    {
        // int temp = data[index];
        // data[index] = oddData[index];
        // oddData[index] = temp;

        oddSum += data[index];  
    } 
}

System.out.println("Even Sum: "  + evenSum);
System.out.println("Odd Sum: "  + oddSum);
System.out.println("Total Sum: "  + sum);

So, you don't need to create extra arrays for even and odd numbers.

And, also your 4 loops have now been condensed to just a single loop.