Count number of occurrences of a digit within a string

Question

So I\'m trying to count the number of occurrences of each digit within an array.

My code I\'ve got so far looks like the following:

#include 

        

Answer 1

You are going to need to arrays - one for the count (result) and one for the input. You should increment the index in the count array as you loop over the input numbers. I couldn't resist actually writing the code so, here you go, the following should work IN C++

#include 
#include 

int main()
{
  int inputNumbers [] = {1, 4, 5, 5, 5, 6, 6, 3, 2, 1};
  int resultCount [] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int countNumbers = sizeof(inputNumbers) / sizeof(inputNumbers[0]);

  for(int i = 0; i < countNumbers; i++)
  {
     resultCount[inputNumbers[i]]++;
  }

  for(int i = 0; i < countNumbers; i++)
  {
    printf("Number %d has occured %d times \n", i, resultCount[i]);
  }
}

Hope that helps.