How can I marshal a hash with arrays?

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醉话见心 2021-01-24 04:23

What should I do to marshal an hash of arrays? The following code only prints {}.

s = Hash.new
s.default = Array.new
s[0] <<          


        
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  •  孤独总比滥情好
    2021-01-24 05:21

    You might be misled about how Hash.default works.

    Before you Marshal.dump, print the data structure. It is {}. That's because you are concatenating each string into nil, not into an empty array. The code below illustrates and solves your problem.

    s = Hash.new
    s.default = Array.new
    s[0] = []
    s[0] << "Tigger"
    s[7] = []
    s[7] << "Ruth"
    s[7] << "Puuh"
    p s
    data = Marshal.dump(s)
    ls = Marshal.restore( data )
    p ls
    

    Returns:

    {0=>["Tigger"], 7=>["Ruth", "Puuh"]}
    {0=>["Tigger"], 7=>["Ruth", "Puuh"]}
    

    EDIT:

    I insert a lot of data into the hash

    So maybe some helper code would make the insertion process smoother:

    def append_to_hash(hash, position, obj)
      hash[position] = [] unless hash[position]
      hash[position] << obj
    end
    
    s = Hash.new
    append_to_hash(s, 0, "Tigger")
    append_to_hash(s, 7, "Ruth")
    append_to_hash(s, 7, "Puuh")
    s.default = Array.new // this is only for reading
    p s
    data = Marshal.dump(s)
    ls = Marshal.restore( data )
    p ls
    

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