function alg1(n) 1 a=0 2 for o=1 to n do 3 for t=1 to o do 4 for k=t to o+t do 5 a=a+1 6 return(a)
If anyone could guide me to how
Subtract t from the last loop so that it becomes
for k=0 to o do
Now the 2 inner most loops would run for O(o^2) time for every value of o. The answer would be
1^2 + 2^2 + ... n^2
which is equal to
n(n+1)(2n+1)/6. Hence it would be of order of O(n^3)