Awk print matched column if exists else print not found

Question

My text file looks like below

date=\"2017-10-10\" ip=192.168.1.1:22 inbound=100 outbound=100
date=\"2017-10-10\" ip=192.168.1.1:22 inbound=100
date=\"2017-10-10         


        

Answer 1

Input

$ cat file
date="2017-10-10" ip=192.168.1.1:22 inbound=100 outbound=100
date="2017-10-10" ip=192.168.1.1:22 inbound=100
date="2017-10-10" ip=192.168.1.1:22  outbound=100

Output

$ awk '{if(match($0,/inbound=[0-9]+/)){s=substr($0,RSTART,RLENGTH); print substr(s,index(s,"=")+1);next}print 0,"Not Found"}' file
100
100
0 Not Found

Explanation

awk '{

    # Search for word inbound=[0-9]+ in record/line/row, if found then
    if(match($0,/inbound=[0-9]+/))
    {
        # Extract word
        s=substr($0,RSTART,RLENGTH)

        # Print value which is after "="  
        print substr(s,index(s,"=")+1)

        # Go to next line
        next
    }

      # If above condition is not true then word inbound not found in line/row/record

      print 0,"Not Found"
  }
 ' file