Scope resolution operator and const

Question

Let\'s take the following code:

#include  // std::string    
using namespace std;
int main() {
  //const::int i = 42;       -> Error: \"expected         


        

Answer 1

const::string is parsed as const ::string. ::string means to look up string in the global namespace, and since you have injected std into the global namespace, std::string is found and everything is dandy.

int is a built-in type and isn't in any namespace, so there's no such thing as ::int or std::int, hence the error.