How can I find the words consist of the letters inside the keyword in Lua?

Question

For example, I have a keyword \"abandoned\" and I want to find the words that contains letters of this keyword such as \"done\", \"abandon\", band\", from the arrays I stored t

Answer 1

For example, I have a keyword "abandoned" and I want to find the words that contains letters of this keyword such as "done", "abandon", band", from the arrays I stored those words. How can I search it?

You can simply use the keyword as a regular expression (aka "pattern" in Lua), using it's letters as a set, for instance ('^[%s]+$'):format('abandoned'):match('done').

local words = {'done','abandon','band','bane','dane','danger','rand','bade','rand'}
local keyword = 'abandoned'

-- convert keyword to a pattern and match it against each word
local pattern = string.format('^[%s]+$', keyword)
for i,word in ipairs(words) do
    local matches = word:match(pattern)
    print(word, matches and 'matches' or 'does not match')
end

Output:

done    matches
abandon matches
band    matches
bane    matches
dane    matches
danger  does not match
rand    does not match
bade    matches
rand    does not match