Iterate over python dictionary to retrieve only required rows

Answer 1

Assuming that there's only one row per version and you don't need the other versions at all you could create a function that parses the HTML and returns dict representing version as soon as it's found. If version is not found it could return None instead:

from xml.etree import ElementTree as ET

s = """

  
Release
REFDB
URL
  
3.7.3
12345
http://google.com
  
3.7.4
456789
http://foo.com

"""

def find_version(ver):
    table = ET.XML(s)
    rows = iter(table)
    headers = [col.text for col in next(rows)]
    for row in rows:
        values = [col.text for col in row]
        out = dict(zip(headers, values))
        if out['Release'] == ver:
            return out

    return None

res = find_version('3.7.3')
if res:
    for x in res.items():
        print(' - '.join(x))
else:
    print 'Version not found'

Output:

Release - 3.7.3
URL - http://google.com
REFDB - 12345