String concatenation in Bash script

Question

I am writing this Bash script:

count=0   
result

for d in `ls -1 $IMAGE_DIR | egrep \"jpg$\"`
do

    if (( (count % 4) == 0 )); then
                result=\"a         


        

Answer 1

Something like this (untested, of course):

count=0 result=

for d in "$IMAGE_DIR"/*jpg; do
   (( ++count % 4 == 0 )) &&
     result="abc $d"
   (( count > 0 )) &&
     printf '%s\n' "$result" ||
      result+=$d
done