Numeration count inside a recursive function

Question

I want do do something like:

>enumerate [\"banana\", \"potato\", \"ice\"]
[(1, \"banana\"), (2, \"potato\"), (3, \"ice\")]

I wrote:

<

Answer 1

As you clarified you wanted to implement your own zip:

zip' [] _ = []
zip' _ [] = []
zip' (x:xs) (y:ys) = (x,y) : zip' xs ys