Sizes of arrays declared with pointers

Question

char c[] = \"Hello\";
char *p = \"Hello\";

printf(\"%i\", sizeof(c)); \\\\Prints 6
printf(\"%i\", sizeof(p)); \\\\Prints 4

My question is:

Why

Answer 1

pointer and array are different.

char c[] = "Hello"; //declare c as an array. sizeof(c) calculate the size of array 6.
char *p = "Hello"; //declare p as a pointer.sizeof(p) calculate the size of pointer,in most machine the size of pointer is 4.

you can also refer to .