I am trying to query my database several times and construct an object which stores every response from my database in a field. Here is my code:
router.post(\'/s
You can do it with Promises
router.post('/search', (req, res) => {
var collection = db.get().collection('styles');
// Create promise for "make.name" query
let firstQuery = new Promise((resolve, reject) => {
collection.distinct('make.name', (err, docs) => {
if (!err) {
resolve(docs);
} else {
reject(err);
}
});
});
// Create promise for "model" query
let secondQuery = new Promise((resolve, reject) => {
collection.distinct('model', (function (err, docs) {
if (!err) {
resolve(docs);
} else {
reject(err);
}
}))
})
// Run both queries at the same time and handle both resolve results or first reject
Promise.all([firstQuery, secondQuery])
.then((results) => {
res.send({ "make.name": results[0], "model": results[1] });
})
.catch((err) => {
// Catch error
res.send({});
});
});
Also you can use destructuring in callback functions like that:
Promise.all([firstQuery, secondQuery])
.then(([makeName, model]) => res.send({ "make.name": makeName, model }))
UPD: If you have a bunch of collection to request you can create an array of collections name, map it to promise requests and handle with Promise.all, for example
let collections = ["firstCollection", "secondCollection", "nCollection"];
let promises = collections.map((collectionName) => {
return new Promise((resolve, reject) => {
collection.distinct(collectionName, (err, docs) => {
if (!err) {
resolve(docs)
} else {
reject(err);
}
});
})
});
Promise.all(promises)
.then(results => {
// Do what you want to do
})
.catch(error => {
// or catch
});