How can I get the value in Firebase Database with android?

Question

My Firebase Realtime Database is like this :

{Singer :
    Billie Eilish :
        01 :
            songType : \"type01\"
            songName : \"bad guy\"
             


        

Answer 1

Since you're passing a reference to Singers into the recycler view, your parseSnapshot is called for each singer. In there you need to make sure you check the songType of each song child of the singer, where now you check the songType of the singers themselves (which never exists, so never goes into the if block).

So it'd be something like this:

Query query = FirebaseDatabase.getInstance().getReference().child("Singer");
options = new FirebaseRecyclerOptions.Builder().setQuery(query, new SnapshotParser() {
    @NonNull
    @Override
    public ItemModel parseSnapshot(@NonNull DataSnapshot snapshot) {
        String song = "No song found";
        for (DataSnapshot songSnapshot: snapshot.getChildren()) {
            String songType = songSnapshot.child("songType").getValue(String.class)
            if (songType.equals("type01") {
              song = songType;
              ...

I'm not sure though if this is what you want, because you seem to want a list of songs, while you're passing in a list of singers. The above will only work if each singer has exactly one song of type01 (not 0, not more).

If that is not the case, the adapters in FirebaseUI won't fit your needs with your current data structure, since they show a list of items from the database, while you want to show items from a tree-like structure.

The two main options that come to mind in that case:

1. Build your own adapter, typically based on ArrayAdapter as shown here.
2. Change your data structure so that all songs are in a flat list (and the singer then becomes a property of each song).