Why do function pointers all have the same value?

Question

For example:

using namespace std;
#include 

void funcOne() {
}

void funcTwo( int x ) {
}

int main() {

  void (*ptrOne)() = funcOne;
  cout &l         


        

Answer 1

Use it like this, or it will be converted to a bool type.

cout << reinterpret_cast(ptrOne) << endl;