How to determine C++ function call order?

Question

I\'ll skip the headers

class X {
    int i;
    static int j;

public:
    X(int ii = 1) : i(ii) {
        j = i;
    }
    static int incr() {
        return ++         


        

Answer 1

This statement

cout << x.f() << xp->f() << X::f();

can be rewritten like

cout.operator <<( x.f() ).operator <<( xp->f() ).operator <<( X::f() );

The order of evaluations of expressions used as arguments in this statement is unspecified. So the compiler can evaluates them for example from left to right or from right to left. Thus using different compilers you can get different results.:)

To get a deterministic result you should rewrite statement

cout << x.f() << xp->f() << X::f();

for example like

cout << x.f();
cout << xp->f();
coit << X::f();