what does x— or x++ do here?

Question

it is a silly Q for most of u - i know - but i one of the beginner here, and I can not understand why the output in here are 12 what does this (x--) do to the resu

Answer 1

x-- will decrement value of x by 1. It is a postfix decrement operator, --x is a prefix decrement operator.

So, what's going on here?

 
int x, y;    //initialize x and y
x = 7;       //set x to value 7
x--;         //x is decremented by 1, so it becomes 6
y = x * 2;   //y becomes 6*2, therefore y becomes 12
x = 3;       //x becomes 3

By analogy, the ++ will increase a value by 1. It also has a prefix and postfix variant.