print bits of a void pointer

Question

If I create a void pointer, and malloc a section of memory to that void pointer, how can I print out the individual bits that I just allocated?

For example:

Answer 1

The malloc allocates bytes.

 for (i = 0; i < 24; ++i) printf("%02xh ", p[i]);

would print the 24 bytes. But if cast to an int, you'll need to adjust the loop:

 for (i = 0; i < 24; i += sizeof(int)) printf("%xh", *(int *)&p[i]);

But then, if you know you want an int, why not just declare it as an int?