print bits of a void pointer

Question

If I create a void pointer, and malloc a section of memory to that void pointer, how can I print out the individual bits that I just allocated?

For example:

Answer 1

You can't - reading those bytes before initializing their contents leads to undefined behavior. If you really insist on doing this, however, try this:

void *buf = malloc(24);
unsigned char *ptr = buf;
for (int i = 0; i < 24; i++) {
    printf("%02x ", (int)ptr[i]);
}

free(buf);
printf("\n");