How can I replace a list with another list that contain the variable to be replaced. for example
rep([x, d, e, z, x, z, p], [x=z, z=x, d=c], R).
R = [z, c, e, x,
Here's how you could proceed using if_/3 and (=)/3.
First, we try to find a single Key
in a list of pairs K-V
.
An extra argument reifies search success.
pairs_key_firstvalue_t([] ,_ ,_ ,false).
pairs_key_firstvalue_t([K-V|KVs],Key,Value,Truth) :-
if_(K=Key,
(V=Value, Truth=true),
pairs_key_firstvalue_t(KVs,Key,Value,Truth)).
Next, we need to handle "not found" cases:
assoc_key_mapped(Assoc,Key,Value) :-
if_(pairs_key_firstvalue_t(Assoc,Key,Value),
true,
Key=Value).
Last, we put it all together using the meta-predicate maplist/3:
?- maplist(assoc_key_mapped([x-z,z-x,d-c]), [x,d,e,z,a,z,p], Rs).
Rs = [z,c,e,x,a,x,p]. % OK, succeeds deterministically