Display query result in a table

Question

I have a MySQL query with over 50 return results. Now I need to display the results in a table with 3 rows and 3 columns.

Something like this:

Answer 1

try something like:

 echo "";
 while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
 $name   = $row['name'];
 $address = $row['address'];
 $content = $row['content'];
 echo "";
 }
 echo "
".$name."
".$address."
".$content."
";

this example will print in table all the result of the query. if you want to limit only to some results, so limit the sql query. for example:

 $q = "SELECT name, address, content FROM mytable limit 50"; 

to get each content,name, address in TD, and 3 of mycontent(content, name, address) in a TR try this:

$c= mysql_query("select COUNT(name) from mytable");
$n=mysql_fetch_array($c);
$maxname= $n[0];
$i=0;
$tr=0;
echo "";
while ($tr < $maxname)
{ 
echo "";
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC) and $i<$tr) {
$name   = $row['name'];
$address = $row['address'];
$content = $row['content'];
echo "";
$i++;
}
echo "";
$tr= $tr+3;
}
echo "
".$name." | ".$address." | ".$content."
";