hide function template, declare specializations

Question

This is a followup to C++ templates: prevent instantiation of base template

I use templates to achieve function overloading without the mess of implicit type conversions

Answer 1

The best way is to implement that basic template with something invalid (not illegal) C++ code. For example,

template T f(T v) { return v.Default_Implementation_Not_Available; }

This error will be compile time; and it's generated only when you instantiate any version other than 'long' & 'bool'. If you don't instantiate 'int' version, compilation will go fine.