Python, unable to convert input() to int()

Question

I am trying to convert input() data to int() with the following code:

prompt_text = \"Enter a number: \"
try:
  user_num = int(input(prompt_text))
except ValueEr         


        

Answer 1

The problem isn't with the conversion to an int. user_num doesn't get a value if an exception is thrown, but it's used later.

prompt_text = "Enter a number: "
try:
  user_num = int(input(prompt_text)) # this fails with `asd2`
except ValueError:
  print("Error") # Prints your error

for i in range(1,10):
  print(i, " times ", user_num, " is ", i*user_num) # user_num wasn't assigned because of the error

even = ((user_num % 2) == 0)

if even:
  print(user_num, " is even")
else:
  print(user_num, " is odd")

You can fix this by putting the code that uses user_num in the try-block. I'll also add create a function to clean things up.

def is_even(num):
  return num%2 == 0

prompt_text = "Enter a number: "
try:
  user_num = int(input(prompt_text))
  for i in range(1,10):
    print(i, " times ", user_num, " is ", i*user_num)
  if is_even(user_num):
    print(user_num, " is even")
  else:
    print(user_num, " is odd")
except ValueError:
  print("Error")

See the ideone here.