Template argument deduction when the function returns a type composed from the template type and another
The title is rather hard to formulate in word, but here is what I\'m trying to achieve in non-compileable code:
template class Conta
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Your only trouble here is that
std::vectoris not atemplate. It is aclass templatethat happens to have a default argument for the second template parameter.class One way around this is using an alias template that really does take just one parameter:
#includetemplate class Container> Container foo() { return Container {1,2,3}; } template using Vec = std::vector ; int main() { auto bar = foo (); return 0; } Another approach recommended in the comments is to use a variadic typename when declaring the template of the original function, which accepts any class template taking only type arguments. And then you can instantiate it with just one argument, since the actual template has a default for the second. This works in C++11 and above.
#includetemplate class Container> Container foo() { return Container {1,2,3}; } int main() { auto bar = foo
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